sin^2(x)+9cos^2(x)=5sin(2x)

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Solution for sin^2(x)+9cos^2(x)=5sin(2x) equation: 


Simplifying
sin2(x) + 9cos2(x) = 5sin(2x)

Multiply in2s * x
in2sx + 9cos2(x) = 5sin(2x)

Multiply cos2 * x
in2sx + 9cos2x = 5sin(2x)

Reorder the terms:
9cos2x + in2sx = 5sin(2x)

Remove parenthesis around (2x)
9cos2x + in2sx = 5ins * 2x

Reorder the terms for easier multiplication:
9cos2x + in2sx = 5 * 2ins * x

Multiply 5 * 2
9cos2x + in2sx = 10ins * x

Multiply ins * x
9cos2x + in2sx = 10insx

Solving
9cos2x + in2sx = 10insx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2sx' to each side of the equation.
9cos2x + in2sx + -1in2sx = 10insx + -1in2sx

Combine like terms: in2sx + -1in2sx = 0
9cos2x + 0 = 10insx + -1in2sx
9cos2x = 10insx + -1in2sx

Divide each side by '9os2x'.
c = 1.111111111ino-1s-1 + -0.1111111111in2o-1s-1

Simplifying
c = 1.111111111ino-1s-1 + -0.1111111111in2o-1s-1

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